(2x^2+16x+49)=0

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Solution for (2x^2+16x+49)=0 equation:


Simplifying
(2x2 + 16x + 49) = 0

Reorder the terms:
(49 + 16x + 2x2) = 0

Remove parenthesis around (49 + 16x + 2x2)
49 + 16x + 2x2 = 0

Solving
49 + 16x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
24.5 + 8x + x2 = 0

Move the constant term to the right:

Add '-24.5' to each side of the equation.
24.5 + 8x + -24.5 + x2 = 0 + -24.5

Reorder the terms:
24.5 + -24.5 + 8x + x2 = 0 + -24.5

Combine like terms: 24.5 + -24.5 = 0.0
0.0 + 8x + x2 = 0 + -24.5
8x + x2 = 0 + -24.5

Combine like terms: 0 + -24.5 = -24.5
8x + x2 = -24.5

The x term is 8x.  Take half its coefficient (4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
8x + 16 + x2 = -24.5 + 16

Reorder the terms:
16 + 8x + x2 = -24.5 + 16

Combine like terms: -24.5 + 16 = -8.5
16 + 8x + x2 = -8.5

Factor a perfect square on the left side:
(x + 4)(x + 4) = -8.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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